Examples of 'are disjoint' in a sentence
Meaning of "are disjoint"
are disjoint: This phrase is used to describe two or more things that are separate, disconnected, or not related to each other in any way. It is often used in mathematical or logical contexts to indicate that there is no overlap or intersection between the sets or elements being discussed
How to use "are disjoint" in a sentence
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are disjoint
Events are disjoint if they have no outcomes in common.
Two blocks are adjacent when they are disjoint.
They are disjoint except for equality.
The first two examples are disjoint.
Two sets are disjoint if they have no elements in common.
The regions that make up a region page are disjoint.
Two events are disjoint if they have no elements in common.
The entities person and collective agent are disjoint.
Sets are disjoint if they do not share any elements.
The two images are disjoint.
They are disjoint and do not link much to each other.
Because the intervals are disjoint.
These two phases are disjoint and may be implemented independently.
Two vertices are adjacent when the corresponding subsets are disjoint.
The exposure classes below are disjoint among themselves.
See also
Sets are disjoint if and only if their intersection is the empty set.
Thus all members are disjoint.
Classes are disjoint if they can not have any instances in common.
Or whether there are disjoint.
Alias classes are disjoint sets of locations that can not alias to one another.
Many systems allow us to specify explicitly that several classes are disjoint.
The unions are disjoint unions.
This follows since no two open sets of the cofinite topology are disjoint.
Thus they are disjoint.
A and B are disjoint if their intersection is the empty set.
The powers are disjoint.
In another embodiment, the two sets of antennas are disjoint.
Two sets of resource elements which are disjoint can also be referred to as orthogonal.
The first supporting panel and the second supporting panel are disjoint structures.
Sets are disjoint.
Social choice and public choice theory may overlap but are disjoint if narrowly construed.
The S interlaces are disjoint in that each of the K subbands belongs in only one interlace.
The only graphs that are locally complete are disjoint unions of complete graphs.
And notice, these are disjoint sets, which gradually fill up all possible composites.
For entities, any constraints are explicitly given, such as when two entities are disjoint.
Disjoint Two geometries are disjoint if their intersection is empty.
Note that the first, the second, and the third frequency sets are disjoint frequency sets.
Thus, two trapezoids are disjoint exactly if their corresponding boxes are comparable.
A space is hyper-connected if no two non-empty open sets are disjoint.
Equivalently, two sets are disjoint if their intersection is the empty set.
A space is ultra-connected if no two non-empty closed sets are disjoint.
Equivalently, two events are disjoint if their intersection is the empty set.
To Prove: Given two CFLs, the problem of deciding whether the CFLs are disjoint.
Advantageously, the n rows of any one group are disjoint so as to avoid coupling dissymmetries.
Thus, in this variant, the sequences SM and SO are disjoint.
These sets are disjoint because P is a prefix-free set.
Note that this only works if the sets a, b, c, … are disjoint.
The elements of P are disjoint two by two ;.
Each type picks a strategy from a strategy set S i { \ displaystyle S _ { i } }, which we assume are disjoint.
Thus the sets and are disjoint ( this is trivial if ).
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Our state to be disjoint and out of frame
However they do not form a disjoint set
Events are disjoint if they have no outcomes in common
